• Danny M@lemmy.escapebigtech.info
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    1 year ago

    Definitely, tho if you store it as a u32 that is fixed magically. Because 1.2.3.4 and 1.02.003.04 both map to the same number.

    What I mean by storing it as a u32 is to convert it to a number, similar to how the IP gets sent over the wire, so for v4:

    octet[3] | octet[2] << 8 | octet[1] << 16 | octet[0] << 24

    or in more human terms:

    (fourth octet) + (third octet * 256) + (second octet * 256^2) + (first octet * 256^3)
    
    • Emma_Gold_Man@lemmy.dbzer0.com
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      1 year ago

      True enough for database or dictionary storage, but a lot of times things get implemented in arrays where you still wind up with two copies of the same uint32.

    • p1mrx@sh.itjust.works
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      1 year ago

      Because 1.2.3.4 and 1.02.003.04 both map to the same number.

      But 10.20.30.40 and 010.020.030.040 map to different numbers. It’s often best to reject IPv4 addresses with leading zeroes to avoid the decimal vs. octal ambiguity.