In a really twisted way, Youtube is a fairly big reason why a good number of people go outside, take up hobbies, etc.

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There are very very few entertainers that have ever choked me up, but damn Richard Simmons and Newhart are definitely on that list. Rest well.

Well, if “media” is in general, I’d have to say television. I’ll watch some things once in a while, but for the most part, I have way too much anxiety from a bad marriage. Audio books, and certain Youtube channels can trigger it, too.

I’m rather curious about this, too.

I’ll chime in with what I’ve personally dealt with.

Both Aroma brand

Glass lid, metal cooking pan has a lip that rolls outside of the heating base. Just a simple switch, cooking & warm. Does boil over once in a while, and fairly small…ease of cleaning, really really easy.

Enclosed unit, has a metal pan that goes inside and a steamer basket, has a removeable metal top to clean…haven’t had it for long, but I can imagine the seals will deteriorate and make it not as long lasting as the other pan…However, those seals do make cleaning more difficult.

I used to drink root beer out of the licorice red vines, those held up quite well. Though, the lart was around seven years ago. I haven’t seen blaok red vines in ages around these parts.

Have no idea if the red ones would have held up. Never liked those too much, heh, and other than root beer, birch beer, I’d drink coffee instead.

This…So much thie…but red vines rather than twizzler. They have a much bigger hole.

I did find that it can be done arbitrarily. Mind is definitely not into writing about it, though, but here’s the gp code I wrote to look it over.

/*
    There may exist a 0<=t<s such that
    s divides both x and (x+(x%d)*(t*d-1))/d.


    To show this for solving for divisibility of 7 in 
    any natural number x.

    g(35,5,10) = 28
    g(28,5,10) = 42
    g(42,5,10) = 14
    g(14,5,10) = 21
    g(21,5,10) =  7
*/

g(x,t,d)=(x+(x%d)*(t*d-1))/d;

/* Find_t( x = Any natural number that is divisible by s,
           s = The divisor the search is being done for,
           d = The modulus restriction ).

    Returns all possible t values.
*/

Find_t(x,s, d) = {
    V=List();
    
    for(t=2,d-1,
        C = factor(g(x,t,d));
        for(i=1,matsize(C)[1],if(C[i,1]==s, listput(V,t))));
        
    return(V);
}   

One thing that I noticed almost right away, regardless what d is, it seems to always work when s is prime, but not when s is composite.

Too tired…Pains too much…Have to stop…But still…interesting.

Yeah, before my mind decided it didn’t like learning any more, I had learned the gist of Bell and Noll’s calc, then switched to gp a few years later…for which I can not remember why, but I can still remember how to use it fairly well.

Not sure, (“Older and a lot more decrepit” doesn’t mean “younger an a lot more mentally sound”, heh. Do wish I could change that, but meh, I can’t).

Anyway, I did find a method similar to what you wrote, so I can redefine it in your terms.

A base 20 number is divisible by 7 if the difference between 8 times the last digit and the remaining digits is divisible by 7.

Ok, a little description on a base 20 number (Think Mayan and Nahuatl/Aztec numbers). 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19 should be considered single digits. So a base 10 number, 7*17 = 119 (1*10^2+1*10+9), would be 7*17 = 5:19 in a base 20 system (5*20+19).

• is 1:8 divisible by 7? (28 in base 10). 8*8 = 3:4. 3:4-1 = 3:3
  • is 3:3 divisible by 7? 8 * 3 = 1:4. 1:4 - 3 = 1:1 (1*20+1 = 21).
• is 9:2 divisible by 7? (182). 2*8 = 16. 16-9 = 7 Check.

I’ll just leave that there. So a long weird way of saying, yes, that’s pretty much my reasoning, but not exactly at the same time. As the first message included the base 20 numbers divisible by the base 20 single digits 7, 13, and 17. (Hopefully that came off a little better).

(Note: Saying “base 20 number[s]” is not important overall. Just being overly descriptive to differentiate between base 10 digits and base 20 digits).